Jump to content

Assignment operator (C++)

From Wikipedia, the free encyclopedia
(Redirected from Copy assignment operator)

In the C++ programming language, the assignment operator, =, is the operator used for assignment. Like most other operators in C++, it can be overloaded.

The copy assignment operator, often just called the "assignment operator", is a special case of assignment operator where the source (right-hand side) and destination (left-hand side) are of the same class type. It is one of the special member functions, which means that a default version of it is generated automatically by the compiler if the programmer does not declare one. The default version performs a memberwise copy, where each member is copied by its own copy assignment operator (which may also be programmer-declared or compiler-generated).

The copy assignment operator differs from the copy constructor in that it must clean up the data members of the assignment's target (and correctly handle self-assignment) whereas the copy constructor assigns values to uninitialized data members.[1] For example:

My_Array first;           // initialization by default constructor
My_Array second(first);   // initialization by copy constructor
My_Array third = first;   // Also initialization by copy constructor
second = third;           // assignment by copy assignment operator

Return value of overloaded assignment operator

[edit]

The language permits an overloaded assignment operator to have an arbitrary return type (including void). However, the operator is usually defined to return a reference to the assignee. This is consistent with the behavior of assignment operator for built-in types (returning the assigned value) and allows for using the operator invocation as an expression, for instance in control statements or in chained assignment. Also, the C++ Standard Library requires this behavior for some user-supplied types.[2]

Overloading copy assignment operator

[edit]

When deep copies of objects have to be made, exception safety should be taken into consideration. One way to achieve this when resource deallocation never fails is:

  1. Acquire new resources
  2. Release old resources
  3. Assign the new resources' handles to the object
class My_Array{
    int* array;
    int count;
public:
    My_Array& operator=(const My_Array& other)
    {
        if (this != &other) { // protect against invalid self-assignment
            // 1: allocate new memory and copy the elements
            int* new_array = new int[other.count];
            std::copy(other.array, other.array + other.count, new_array);

            // 2: deallocate old memory
            delete[] array;

            // 3: assign the new memory to the object
            array = new_array;
            count = other.count;
        }
        // by convention, always return *this
        return *this;
    }
    // ...
};

However, if a no-fail (no-throw) swap function is available for all the member subobjects and the class provides a copy constructor and destructor (which it should do according to the rule of three), the most straightforward way to implement copy assignment is as follows:[3]

public:

    void swap(My_Array& other) // the swap member function (should never fail!)
    {
        // swap all the members (and base subobject, if applicable) with other
        using std::swap; // because of ADL the compiler will use 
        // custom swap for members if it exists
        // falling back to std::swap
        swap(array, other.array);
        swap(count, other.count);
    }

    My_Array& operator = (My_Array other) // note: argument passed by value!
    {
        // swap this with other
        swap(other);

        // by convention, always return *this
        return *this;

        // other is destroyed, releasing the memory
    }

Assignment between different classes

[edit]

C++ supports assignment between different classes, both via implicit copy constructor and assignment operator, if the destination instance class is the ancestor of the source instance class:

class Ancestor {
public:
    int a;
};

class Descendant : public Ancestor {
public:
    int b;
};

int main()
{
    Descendant d;
    Ancestor a(d);
    Ancestor b(d);
    a = d;
}

Copying from ancestor to descendant objects, which could leave descendant's fields uninitialized, is not permitted.

See also

[edit]

References

[edit]
  1. ^ Stroustrup, Bjarne (2000). The C++ Programming Language (3 ed.). Addison-Wesley. p. 244. ISBN 978-0-201-70073-2.
  2. ^ Working Draft, Standard for Programming Language C++, Section 17.6.3.1, Table 23; http://www.open-std.org/jtc1/sc22/wg21/docs/papers/2012/n3337.pdf
  3. ^ Sutter, H.; Alexandrescu, A. (October 2004), C++ Coding Standards, Addison-Wesley, ISBN 0-321-11358-6
[edit]